MCQ
Which of the following is planar ?
- ✓$XeF_4$
- B$XeO_4$
- C$XeO_2F_2$
- D$XeOF_4$
As $6$ electron pairs are three $Xe F_4$ structure should be octahedral but it square planar due to two lone pairs on it.
Because of two lone pairs repulsions increases and shape becomes square planar.
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The product $'B'$ is?
$(i)\,\, Cl^-$ can give up an electron more easily than $F^-$
$(ii) \,\,Cl^-$ is a better reducing agent than $F^-$
$(iii)\,\, Cl^-$ is smaller in size than $F^-$
$(iv)\,\, F^-$ can be oxidized more readily than $Cl^-$
