MCQ
Which of the following is probability density function for standard normal variable?
  • A
    $f(z)=e^{-\frac{1}{2} z^2} ;-\infty < z < \infty$
  • B
    $f(z)=\frac{1}{\sqrt{2 \pi}} e^{-\frac{1}{2} z^2} ;-\infty < z < \infty$
  • C
    $f(z)=\frac{1}{\sqrt{2 \pi}} e^{-\frac{1}{2} z^2} ; 0 < z <\infty$
  • $f(z)=\frac{1}{\sqrt{2 \pi}} e^{-\frac{1}{2} z^2} ;-\infty < z < \infty$

Answer

Correct option: D.
$f(z)=\frac{1}{\sqrt{2 \pi}} e^{-\frac{1}{2} z^2} ;-\infty < z < \infty$

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