MCQ
Which of the following is the correct order for increasing bond angle ?
- A$NH_3 < PH_3 < AsH_3 < SbH_3$
- B$H_2O < OF_2 < Cl_2O$
- C$H_3Te^+ < H_3Se^+ < H_3S^+ < H_3O^+$
- D$BF_3 < BCl_3 < BBr_3 < BI_3$
$(b)\, OF_2 < OH_2 < OCl_2$
$(c)\, H_3Te^+ < H_3Se^+ < H_3S^+ < H_3O^+$
$(d)\, BF_3 = BCl_3 = BBr_3 = BI_3$
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$(A)$ Uncertainty principle rules out the existence of definite paths for electrons.
$(B)$ The energy of an electron in $2 s$ orbital of an atom is lower than the energy of an electron that is infinitely far away from the nucleus.
$(C)$ According to Bohr's model, the most negative energy value for an electron is given by $n=1$, which corresponds to the most stable orbit.
$(D)$ According to Bohr's model, the magnitude of velocity of electrons increases with increase in values of $n$.