- AAluminium
- ✓Magnesium
- CPhosphorus
- DSulphur
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$C{H_2} = C{H_2}\xrightarrow[{oxid}]{{Hypochloro}}$ $M\xrightarrow{R}\begin{array}{*{20}{c}}
{C{H_2} - OH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_2} - OH}
\end{array}$
Where $M$ = molecule; $R$ = reagent $M$ and $R$ are
[Given : $p K _{ a 1}$ and $p K _{ a 2}$ of $H _2 CO _3$ are $6.37$ and $10.32 $, respectively $; \log 2=0.30$ ]
$(i)\,Cl\xrightarrow{E.A.}Cl^-\,\,\,\,\,\,(ii)\,C{{l}^{-}}\xrightarrow{I.E.}Cl\,\,\,\,(iii)\,\,Cl\xrightarrow{I.E.}C{{l}^{+}}\,\,\,(iv)\,\,C{{l}^{+}}\xrightarrow{I.E.}Cl^{2+}$
$(A) i)$ Lindlar's catalyst, $H _2$; $ii$) $SnCl _2 / HCl$; iii) $NaBH _4$; iv) $H _3 O ^{+}$
$(B) i)$ Lindlar's catalyst, $H _2$; $ii$) $H _3 O ^{+}; iii)$ $SnCl _2 / HCl$; iv) $NaBH _4$
$(C) i)$ $NaBH _4; ii)$ $SnCl _2 / HCl; $iii$)$ $H _3 O ^{+}; iv)$ Lindlar's catalyst, $H _2$
$(D) i)$ Lindlar's catalyst, $H _2$; $ii$) $NaBH _4; iii)$ $SnCl _2 / HCl; iv)$ $H _3 O ^{+}$