MCQ
Which of the following order is correct ?
- A$He > Ne > Ar > Kr$ (Adsorption tendency)
- B$He > Ne > Ar > Kr$ (Critical temperature)
- C$He > Ne > Ar > Kr$ (Boiling point)
- ✓$Xe > Kr > Ar > Ne$ (Polarisation)
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$(I)\,\begin{array}{*{20}{c}}
{C{H_3}CHC{H_2}C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,} \\
{Cl\,\,\,\,\,\,\,\,\,}
\end{array}$
$(II)\,CH_3CH_2CH_2Cl$
$(III)\,H_3CO-C_6H_4-CH_2Cl$
$\underset{{{C}_{3}}{{H}_{6}}C{{l}_{2}}}{\mathop{A}}\,\,\xrightarrow[2.\,\,{{H}^{+}}\,\,(\min d)]{\begin{smallmatrix}
1\,.\,\,alcoholic\,\,KOH\,/\,\Delta \\
followed\,\,by\,\,NaN{{H}_{2}}\,/\,\Delta
\end{smallmatrix}}$ $B\,\xrightarrow[{{H}_{2}}{{O}_{2}}/\overset{\Theta }{\mathop{O}}\,H]{{{B}_{2}}{{H}_{6}}}C$
$A\,\xrightarrow{aq.\,\,KOH\,(excess)}C$
Nucleophile added in this reaction