- ✓$C{H_3} - CH = C{H_2}\,\xrightarrow[{{H_2}{O_2}}]{{HBr}}$
- B$C{H_3} - CH = C{H_2}\,\xrightarrow{{HCl}}$
- C

- D



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$(I)$ ${O_3} \to $ product
$(II)$ $C{r_2}O_7^{2 - }\xrightarrow{{{H^ + }}}$ product
$(III)$ $MnO_4^\Theta \xrightarrow{{{H^ + }}}$ product
$(IV)$ $H_2S \longrightarrow $ product

$Q (47 \%)$ and $R (2 \%)$. The major product(s) of the following reaction sequence is (are)
$\begin{array}{l}\begin{array}{ll}\text { 1) } Ac _2 O \text {, pyridine } \quad \text { 1) } Sn / HCl \end{array} \\ R \xrightarrow{2) Br _2, CH _3 CO _2 H } S \quad \xrightarrow{2) Br _2 / H _2 O \text { (excess) }} \text { major product(s) } \\ \text { 3) } H _3 O ^{+} \quad \text {3) } NaNO _2, HCl / 273-278 K \\ \text { 4) } NaNO _2, HCl / 273-278 K \quad \text { 4) } H _3 PO _2 \\ \text { 5) } EtOH , \Delta \\\end{array}$