
- AOnly (i)
- BOnly (ii)
- CBoth (i) and (ii)
- DNone of these

Explanation:
Since in (ii) reaction configuration is retained so it undergoes by sN' mechanism as in SN2 inversion of configuration occur.
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At what value of $(n)$ given compound will not evolve $CO_2$ gas ?
$\underset{{{C}_{3}}{{H}_{6}}C{{l}_{2}}}{\mathop{A}}\,\,\xrightarrow[2.\,\,{{H}^{+}}\,\,(\min d)]{\begin{smallmatrix}
1\,.\,\,alcoholic\,\,KOH\,/\,\Delta \\
followed\,\,by\,\,NaN{{H}_{2}}\,/\,\Delta
\end{smallmatrix}}$ $B\,\xrightarrow[{{H}_{2}}{{O}_{2}}/\overset{\Theta }{\mathop{O}}\,H]{{{B}_{2}}{{H}_{6}}}C$
$A\,\xrightarrow{aq.\,\,KOH\,(excess)}C$
Reason : $V_2O_5$ or $Pt$ is used in the preparation of $H_2SO_4$ by contact process.
$C{l_2}\,(1\,{\mkern 1mu} atm)|\,\,(C{l^ - }(1{\mkern 1mu} M)||C{l^ - }\,(0.1{\mkern 1mu} M)|\,\,C{l_2}\,(2\,{\mkern 1mu} atm)$