MCQ
Which of the following relations is correct
- A$\sin 1 < \sin 1^\circ $
- ✓$\sin 1 > \sin 1^\circ $
- C$\sin 1 = \sin 1^\circ $
- D$\frac{\pi }{{180}}\sin \,\,\,1\, = \sin \,\,\,{1^o}$
Since value of $\sin \theta $ is increasing $\left[ {0 \to \frac{\pi }{2}} \right]$.
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$f(x)=\sin \left(\frac{\pi x}{12}\right) \text { and } g(x)=\frac{2 \log _{ e }(\sqrt{x}-\sqrt{\alpha})}{\log _{ e }\left( e ^{\sqrt{x}}- e ^{\sqrt{\alpha}}\right)} \text {. }$
Then the value of $\lim _{ x \rightarrow \alpha^{+}} f( g ( x ))$ is