MCQ
Which of the following shall form an octahedral complex
- A${d^4}$ (low spin)
- B${d^8}$ (high spin)
- ✓${d^6}$ (low spin)
- DNone of these
✓
Answer
Correct option: C.
${d^6}$ (low spin)
c
(c) The compounds which show ${d^6} - $ configuration are octahedral complexes.
(c) The compounds which show ${d^6} - $ configuration are octahedral complexes.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
If current $(I)$ of an electrolytic cell is doubled and time $(t)$ for electrolysis is halved then $\frac{mass}{eq.wt.}$ ratio becomes :-
→A flask contains a mixture of compounds $A$ and $B.$ Both compounds decompose by first-order kinetics. The half-lives for $A$ and $B$ are $300$ $s$ and $180\, s ,$ respectively. If the concentrations of $A$ and $B$ are equal initially, the time required for the concentration of $A$ to be four times that of $B ($ in $s ):$ (Use $\ln 2=0.693)$
→
Van't Hoff factor $i$
→Arrange their stabilities of given gem - dials in decreasing order.
Assertion : The free gaseous $Cr$ atom has six unpaired electrons
→Reason : Half-filled s orbital has greater stability.
product $(4)$ in the above reaction is
→In the given reaction $\begin{array}{*{20}{c}}
{{C_6}{H_5} - C - C{H_3}} \\
{||} \\
O
\end{array}$ $\xrightarrow{{N{H_2}OH/{H^ \oplus }}}X\xrightarrow{{Na/{C_2}{H_5}OH}}Y$. $Y$will be
→{{C_6}{H_5} - C - C{H_3}} \\
{||} \\
O
\end{array}$ $\xrightarrow{{N{H_2}OH/{H^ \oplus }}}X\xrightarrow{{Na/{C_2}{H_5}OH}}Y$. $Y$will be
True statement for $NO_3^-$ is
→$(a)$ coordination number of $'N'$ is $3$ , and the structure is triagonal planar
$(b)$ formal charge on $N$ is $+1$
$(c)$ Average formal charge on $'O'$ is $-2/3$
$(d)$ Average bond order of $NO$ bond is $4/3$
$(e)$ All $NO$ bond lengths are identical
Correct code is
Which of the following compounds have highest melting point?
Boiling point of alcohol is comparatively higher than that corresponding alkane due to