- AButene $-2$
- ✓$2, 2-$ dimethylpropane
- CButyne $-1$
- DButanol $-3$
Option $B$ will give $1$ mono brominated products, as $Br$ can go on $C _1$.
Option $C$ will give $1$ mono brominated products, as $Br$ can go on $C _1 / C _2 / C _3 / C _4$.
Option $D$ will give $2$ mono brominated products, as $Br$ can go on $C _1 / C _2 / C _3 / C _4$.
Therefore,Option $B$ is correct answer for this question.
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${H_2}O(g) + C(s) \to CO(g) + {H_2}(g);\,\Delta H = 131\,kJ$$CO(g) + \frac{1}{2}{O_2}(g) \to C{O_2}(g);\Delta H = - 282\,kJ$
${H_2}(g) + \frac{1}{2}{O_2}(g) \to {H_2}O(g);\,\Delta H = - 242\,kJ$
$C(s) + {O_2}(g) \to C{O_2}(g);\,\Delta H = X\,kJ$ The value of $X$ is ......$kJ$
$C{H_4}(g) + 2{O_2}(g) \to C{O_2}(g) + 2{H_2}O(l)$ ;
${\Delta _r}{H_{300}} = - 212.7\ Kcal / mol$ .
The absolute value of ${\Delta _r}U_{300}^o$ for this reaction is .......$Kcal\,/\,mol$ $(R = 2\ cal/mol-K)$