- A$\mathrm{PbF}_4$
- B$\mathrm{PbCl}_4$
- C$\mathrm{PbO}_2$
- ✓$\mathrm{PbI}_4$
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$(I)$ $\begin{array}{*{20}{c}}
{C{H_2} - C{H_2} - C{H_2} - C{H_2}OH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{N{O_2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
$(II)$ $\begin{array}{*{20}{c}}
{C{H_3} - C{H_2} - CH - C{H_2}OH} \\
{|\,} \\
{N{O_2}}
\end{array}$
$(III)$ $\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2} - C{H_2}OH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{N{O_2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
$(IV)$ $CH_3-CH_2-CH_2-CH_2OH$
Select answer from codes given below :
$(p)$ $\begin{matrix}
Ph\,\,\,\,\,O\, \\
|\,\,\,\,\,\,\,\,||\,\, \\
Ph-C-C-C{{H}_{3}} \\
|\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}\,\,\,\,\,\,\,\, \\
\end{matrix}$ $(q)$ $\begin{matrix}
\,Ph\,\,\,\,\,O\, \\
\,\,|\,\,\,\,\,\,\,\,|| \\
Ph-C-C-Et \\
|\,\,\,\,\,\,\,\,\,\, \\
Et\,\,\,\,\,\,\,\,\,\, \\
\end{matrix}$
$(r)$ $\begin{matrix}
\,Ph\,\,\,\,\,O\, \\
|\,\,\,\,\,\,\,\,\,\,||\, \\
Ph-C-C-C{{H}_{3}} \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
Et\,\,\,\,\,\,\,\,\,\,\,\,\, \\
\end{matrix}$ $(s)$ $\begin{matrix}
\,\,\,Ph\,\,\,\,\,O\, \\
\,\,|\,\,\,\,\,\,\,\,|| \\
Ph-C-C-Et \\
|\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}\,\,\,\, \\
\end{matrix}$
When $(A)$ and $(B)$ reacts with $H_2SO_4$ products obtained are
$A$ is