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$R, S$ and $\mu$ respectively are
${N_2}\left( g \right) + {O_2}\left( g \right)\underset{{{k_2}}}{\overset{{{k_1}}}{\longleftrightarrow}}2NO\left( g \right)$
$C_0 = Ce^{-2.1×10^{-3}\ t}$ for the forward reaction and
$C_0'= C'e^{-4.2×10^{-4}\ t}$ for the backward reaction, hence $K_c$ for the above equilibrium is
$(a)\,0.075\,\,M\,CuS{O_4}$ $(b)\,0.060\,\,M\,(NH_4)_2SO_4$
$(c)\,0.14\,\,M\,urea$ $(d)\,0.04\,M\,MgCl_2$
| Column $I$ | Column $II$ |
| $(A)$ $\mathrm{Bi}^{3+} \longrightarrow(\mathrm{BiO})^{+}$ | $(P)$ Heat |
| $(B)$ $\left[\mathrm{AlO}_2\right]^{-} \longrightarrow \mathrm{Al}(\mathrm{OH})_3$ | $(Q)$ Hydrolysis |
| $(C)$ $\mathrm{SiO}_4^{4-} \longrightarrow \mathrm{Si}_2 \mathrm{O}_7^{6-}$ | $(R)$ Acidification |
| $(D)$ $\left(\mathrm{B}_4 \mathrm{O}_7^{2-}\right) \longrightarrow\left[\mathrm{B}(\mathrm{OH})_3\right]$ | $(S)$ Dilution by water |