- AThe spin magnetic moment of $KO_2$ is $1.73\,BM$
- BThe hybridisation of $B$ in $H_3BO_3$ is $sp^2$
- CIn $H_2S_2O_8\, S-S$ linkage is present
- ✓In $ClF_3$ axial and Equatorial bonds are not identical
The valence shell electron configuration of first excited state of sulphur is $3 \mathrm{s}^{2} 3 \mathrm{p}^{3} 3 \mathrm{d}^{1}$
The valence shell electron configuration of second excited state of sulphur is $3 \mathrm{s}^{1} 3 \mathrm{p}^{2} 3 \mathrm{d}^{2}$.
This is followed by sp ${ }^{3} \mathrm{d}^{2}$ hybridization to form $\mathrm{SF}_{6}$.
Thus $\mathrm{SF}_{6}$ is formed in the second excitation state of sulphur atom.
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$CuI_{(s)} + e^{\circleddash} \to Cu_{(s)} + I^{\circleddash}_{(aq)}$ ; $E^o = -0.17\, V$
$Zn^{+2}_{(aq)} + 2e^{\circleddash} \to Zn_{(s)}$ ; $E^o = -0.76\, V$

$[ C ]$ is $........$
Given :( $\frac{{2.303RT}}{F} = 0.06)$
$s{n^{ + 2}}\left( {1M} \right) + 2C{l^ - }\left( {2M} \right) \rightleftharpoons s{n_{\left( s \right)}} + C{l_2}\left( {1\,atm} \right)$
Given : ${E^o}_{s{n^{ + 2}}/sn} = - 0.14$ ${E^o}_{C{l_2}/C{l^- }} = 1.4\,V$
| Element | $M^{3+}/ M$ | $M^+/M$ |
| $Al$ | $-1.66$ | $+0.55$ |
| $Tl$ | $+1.26$ | $-0.34$ |
Based on these data, which of the following statements is correct ?