

$(2)\, 50/50$ mixture of diastereoisomers is also optically active.
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|
Reaction |
$\Delta H(KJ\,mol^{-1})$ |
$\Delta S(JK^{-1}\,mol^{-1})$ |
|
$I$ $II$ $III$ $IV$ $V$ |
$+98.0$ $-55.5$ $+28.3$ $-40.5$ $+ 34.7$ |
$+14.8$ $-84.6$ $-17.0$ $+24.6$ $0.0$ |
| $List-I$ | $List-II$ |
| $(A)$Glucose $+ HI$ | $(I)$ Gluconic acid |
| $(B)$Glucose $+ Br _{2}$ water | $(II)$ Glucose pentacetate |
| $(C)$Glucose $+$ acetic anhydride | $(III)$ Saccharic acid |
| $(D)$Glucose $+ HNO _{3}$ | $(IV)$ Hexane |
Choose the correct answer from the options given below.
$(I)$ $\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - Cl} \\
{\,\,|} \\
{\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}\xrightarrow[{5\% \,\,water}]{{95\% \,\,\,acetone}}\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - OH} \\
| \\
{\,\,\,\,\,\,C{H_3}}
\end{array}$
$(II)$ $\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - Cl} \\
{\,\,|} \\
{\,\,\,\,\,\,C{H_3}}
\end{array}\xrightarrow[{10\% \,\,water}]{{90\% \,\,\,acetone}}\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - OH} \\
| \\
{\,\,\,\,\,\,C{H_3}}
\end{array}$
$(III)$ $\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - Cl} \\
{\,\,|} \\
{\,\,\,\,\,\,C{H_3}}
\end{array}\xrightarrow[{20\% \,\,water}]{{80\% \,\,\,acetone}}\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - OH} \\
| \\
{\,\,\,\,\,\,C{H_3}}
\end{array}$
$(IV)$ $\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - Cl} \\
{\,\,|} \\
{\,\,\,\,\,\,C{H_3}}
\end{array}\xrightarrow{{100\% \,water}}\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - OH} \\
| \\
{\,\,\,\,\,\,C{H_3}}
\end{array}$
Arrange these reactions in decreasing order of greater proportion of inverted product and select correct answer from the codes given below :