Question
Which of the following will show optical activity ?

Answer

a
$(a)\, (1)$ Compounds which do not have plane & centre of symmetry are optically  active. 

$(2)\, 50/50$ mixture of diastereoisomers is also optically active.

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Among the given pairs in which pair, first compound has higher boiling point than second?
Values of $\Delta H$ and $\Delta S$ for five different reactions are given below. On the basis of these values predict which one of these will be spontaneous at all tempeature

Reaction

$\Delta H(KJ\,mol^{-1})$

$\Delta S(JK^{-1}\,mol^{-1})$

             $I$

$II$

$III$

$IV$

$V$

       $+98.0$

$-55.5$

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$-40.5$

$+ 34.7$

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$0.0$

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$List-I$ $List-II$
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$(B)$Glucose $+ Br _{2}$ water $(II)$ Glucose pentacetate
$(C)$Glucose $+$ acetic anhydride $(III)$ Saccharic acid
$(D)$Glucose $+ HNO _{3}$ $(IV)$ Hexane

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$RMgX\xrightarrow{{\begin{array}{*{20}{c}}
  O \\ 
  {||} \\ 
  {H - C - H} 
\end{array}}}$ $\begin{array}{*{20}{c}}
  {C{H_3} - CH - C{H_2} - OH} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
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$(I)$ $\begin{array}{*{20}{c}}
  {{C_6}{H_5} - CH - Cl} \\ 
  {\,\,|} \\ 
  {\,\,\,\,\,\,\,\,\,C{H_3}} 
\end{array}\xrightarrow[{5\% \,\,water}]{{95\% \,\,\,acetone}}\begin{array}{*{20}{c}}
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  | \\ 
  {\,\,\,\,\,\,C{H_3}} 
\end{array}$

$(II)$ $\begin{array}{*{20}{c}}
  {{C_6}{H_5} - CH - Cl} \\ 
  {\,\,|} \\ 
  {\,\,\,\,\,\,C{H_3}} 
\end{array}\xrightarrow[{10\% \,\,water}]{{90\% \,\,\,acetone}}\begin{array}{*{20}{c}}
  {{C_6}{H_5} - CH - OH} \\ 
  | \\ 
  {\,\,\,\,\,\,C{H_3}} 
\end{array}$

$(III)$ $\begin{array}{*{20}{c}}
  {{C_6}{H_5} - CH - Cl} \\ 
  {\,\,|} \\ 
  {\,\,\,\,\,\,C{H_3}} 
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  {{C_6}{H_5} - CH - OH} \\ 
  | \\ 
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$(IV)$ $\begin{array}{*{20}{c}}
  {{C_6}{H_5} - CH - Cl} \\ 
  {\,\,|} \\ 
  {\,\,\,\,\,\,C{H_3}} 
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  {{C_6}{H_5} - CH - OH} \\ 
  | \\ 
  {\,\,\,\,\,\,C{H_3}} 
\end{array}$

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