MCQ
Which of the given method can't produce $Cl_2$
- AElectrolysis of brine
- BDeacon's process
- ✓Heating $MnO_2$ with conc. $HCl$
- DHeating $KCl$ with conc. $H_2SO_4$
Due to inter electronic repulsions $F - F$ bond becomes weak and easily broken.
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| List $I$ Complex | List $II$ Crystal Field splitting energy $\left(\Delta_0\right)$ |
| $A$ $\left[ Ti \left( H _2 O \right)_6\right]^{2+}$ | $I$ $-1.2$ |
| $B$ $\left[ V \left( H _2 O \right)_6\right]^{2+}$ | $II$ $-0.6$ |
| $C$ $\left[ Mn \left( H _2 O \right)_6\right]^{3+}$ | $III$ $0$ |
| $D$ $\left[ Fe \left( H _2 O \right)_6\right]^{3+}$ | $IV$ $-0.8$ |
$\mathrm{NaOH}+\mathrm{Cl}_{2} \rightarrow(\mathrm{A})+$ side products
(hot and conc.)
$\mathrm{Ca}(\mathrm{OH})_{2}+\mathrm{Cl}_{2} \rightarrow(\mathrm{B})+$ side products
$(dry)$
