MCQ
Which of the reaction defines $\Delta H_f^o$ ?
- ✓$\frac{1}{2}{H_2}(g) + \frac{1}{2}{F_2}(g) \to HF(g)$
- B$CO(g) + \frac{1}{2}{O_2}(g) \to C{O_2}(g)$
- C${C_{{\rm{diamond}}}} + {O_2}(g) \to C{O_2}(g)$
- D${N_2}(g) + 3{H_2}(g) \to 2N{H_3}(g)$
Only $(A)$ follows the definition of $\Delta H _{ f }^0$. Therefore, $(A)$ is correct answer.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
[Given : mass of electron $=9.1 \times 10^{-31} \mathrm{~kg}$, Plank's constant $(\mathrm{h})=6.626 \times 10^{-34} \mathrm{JS}$ ]
(Value of $\pi=3.14$ )