MCQ
Which of these is o, p-directing and deactivating group?
- A−F
- B−Cl
- C−Br
- DAll of these
Explanation:
X− (halogen group) has two effects −I & +M.
Due to the −I group, it reduces the electron density of benzene so halobenzene is less reactive than benzene for electrophilic substitution reaction.
But due to the +M effect, it is ortho, para directing (resonance effect predominates over inductive effect) and in halobenzene, further substitution takes place at ortho and para positions.
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$Cl_2 + 2Br^ - (aq.) \to 2Cl^-(aq.) + Br_2$
$Br_2$ gas thus formed is dissolved into solution of $Na_2CO_3$ and then pure $Br_2$ is obtained by treatment of the solution with
The Gibbs free energy change for the above reaction at $298\, K$ is $x \times 10^{-1} \,k\,J\, mol ^{-1}$;
The value of $x$ is ..... [nearest integer]$\left [\text { Given : } E _{ Cu ^{2} / / Cu }=0.34\, V ; E _{ Sn ^{2} / Sn }^{\ominus}=-0.14 \,V ; F=96500\, C\, mol ^{-1}\right]$
$ArN _{2} Cl \overset{Cu / HCl}{\rightarrow} ArCl + N _{2}$ is known as