Question
Which one among $64^2, 108^2, 292^2, 36^2$ has the last digit $4 ?$
✓
Answer
(i) $64^2$
The unit's digit of 64 is 4
$4 \times 4=16$ (last digit 6)
(ii) $108^2$
The unit's digit of 108 is 8
$8 \times 8=64$ (last digit 4)
(iii) $292^2$
The unit's digit of 292 is 2
$2 \times 2=4$ (last digit 4)
(iv) $36^2$
The unit's digit of 36 is 6
$6 \times 6=36$ (last digit 6)
Therefore, $108^2$ and $292^2$ have 4 as their last digits.
The unit's digit of 64 is 4
$4 \times 4=16$ (last digit 6)
(ii) $108^2$
The unit's digit of 108 is 8
$8 \times 8=64$ (last digit 4)
(iii) $292^2$
The unit's digit of 292 is 2
$2 \times 2=4$ (last digit 4)
(iv) $36^2$
The unit's digit of 36 is 6
$6 \times 6=36$ (last digit 6)
Therefore, $108^2$ and $292^2$ have 4 as their last digits.
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