- ✓$0.01\,M\,\,KOH$
- B$1\,N\,\,KOH\,\,ml$
- C$1\,N\,NaOH\,\,ml$
- D$3.0 \times {10^{ - 7}}\,M$
$pH + pOH = 14$; $pH = 14 - pOH$
$pH = 14 - 2 = 12$
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$2MnO_4^ - + 10{I^ - } + 16{H^ + } \to 2M{n^{2 + }} + 5{I_2} + 8{H_2}O$
The rate of appearance $I_2$ is......$\times {10^{ - 2}}\,M{s^{ - 1}}$
${A_2}\left( g \right) + {B_2}\left( g \right) \rightleftharpoons {C_2}\left( g \right) + {D_2}\left( g \right)$
If we take $1\ mole$ of each of the four gases in a $10\ litre$ container, what would be equilibrium concentration of $A_2(g)$?
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$1.$ Which one of the following reagents is used in the above reaction?
$(A)$ aq. $\mathrm{NaOH}+\mathrm{CH}_3 \mathrm{Cl}$
$(B)$ aq. $\mathrm{NaOH}+\mathrm{CH}_2 \mathrm{Cl}_2$
$(C)$ aq. $\mathrm{NaOH}+\mathrm{CHCl}_3$
$(D)$ aq. $\mathrm{NaOH}+\mathrm{CCl}_4$
$2.$ The electrophile in this reaction is
$(A)$ : $\mathrm{CHCl}$ $(B)$ ${ }^{+} \mathrm{CHCl}_2$
$(C)$ $\mathrm{CCl}_2$ $(D)$. $\mathrm{CCl}_3$
$3.$ The structure of the intermediate $I$ is
$Image$
Give the answer question $1, 2$ and $3.$