MCQ
Which one of the following is an optically active compound
- A$n-$ propanol
- ✓$2-$ chlorobutane
- C$n-$ butanol
- D$4-$ hydroxyheptane
because they contain chiral carbon atom.
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| List-$I$ Species | List-$II$ Electronic distribution |
| $(A)$ $\mathrm{Cr}^{+2}$ | $(I)$ $3 \mathrm{~d}^8$ |
| $(B)$ $\mathrm{Mn}^{+}$ | $(II)$ $3 \mathrm{~d}^3 4 \mathrm{~s}^1$ |
| $(C)$ $\mathrm{Ni}^{+2}$ | $(III)$ $3\mathrm{~d}^4$ |
| $(D)$ $\mathrm{V}^{+}$ | $(IV)$ $3 \mathrm{~d}^5 4 \mathrm{~s}^1$ |
Choose the correct answer from the options given below:

$(R = 0.083\, L\, bar\, K^{-1} \,mol^{-1})$
$CH_3 (CH_2)_8CH_2Br \xrightarrow[benzene]{KCN} CH_3 (CH_2)_8CH_2CN$
