- A$\Delta H_{mix} = 0$
- B$\Delta U_{mix} = 0$
- C$\Delta P = P_{obs} -P_{calculated \,by \,Raoult's\, law} = 0$
- ✓$\Delta G_{mix} = 0$
Since the enthalpy of mixing (solution) is zero, the change in Gibbs energy on mixing is determined solely by the entropy of mixing ( $\Delta S _{\text {solution }}$ ).
So the $\Delta G$ is not zero.
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$\,\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2} - CH - C{H_2} - C{H_3}}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
{\,\,\,\,\,\,\,\,\,Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$ $\xrightarrow[{heat}]{{KOH,\,C{H_3}OH}}$
