- A${N_2}{H_4}$
- B$N{H_2}OH$
- C${(C{H_3})_3}N$
- ✓$H{N_3}$
$(A)$ hydrazoic acid $N _3 H$, dissociates into $N _3$ - and $H +$. Due to the formation of hydrogen ion, it is an acid.
$(B)$ In $N_2H_4$, nitrogen easily donates it's lone pair, so it is a base.
$(C)$ $NH_2 Oh$ is basic because it has hydroxyl ions.
$(D)$ The compound trimethylamine, $\left( CH _3\right)_3 N$, is a weak base when dissolved in water.
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Product $(A)$ of the reaction is
$\begin{array}{*{20}{c}}
O \\
{||} \\
{C{H_3} - C{H_2} - C - C{H_2} - C{H_2}}
\end{array}$
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_3} - C{H_2} - C{H_2} - C - N{H_2}}
\end{array}$