- A${N_2}{H_4}$
- B$N{H_2}OH$
- C${(C{H_3})_3}N$
- ✓$H{N_3}$
$(A)$ hydrazoic acid $N _3 H$, dissociates into $N _3$ - and $H +$. Due to the formation of hydrogen ion, it is an acid.
$(B)$ In $N_2H_4$, nitrogen easily donates it's lone pair, so it is a base.
$(C)$ $NH_2 Oh$ is basic because it has hydroxyl ions.
$(D)$ The compound trimethylamine, $\left( CH _3\right)_3 N$, is a weak base when dissolved in water.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| Element | $IE_1$ | $IE_2$ | $IE_3$ | $IE_4$ |
| $W$ | $10.5$ | $15.5$ | $24.9$ | $79.8$ |
| $X$ | $8$ | $14.8$ | $78.9$ | $105.8$ |
Other two elements $Y$ and $Z$ have outer electronic configuration $ns^2$ $np^4$ and $ns^2$ $np^5$ respectively. According to given information which of the following compound $(s)$ is/are not possible
$(a)\, W_2Y_3\, (b)\, X_2Y_3\, (c)\, WZ_2\, (d)\, XZ_2$
Hyperconjugation occurs in
Reason : Benzene is a solvent for the Friedel- Craft's alkylation of bromobenzene.