- A$VO_2^ + \, \to \,{V_2}{O_3}$
- B$Na\, \to \,N{a^ + }$
- ✓$CrO_4^{2 - }\, \to \,C{r_2}O_7^{2 - }$
- D$Z{n^{2 + }}\, \to \,Zn$
$x + [( - 2) \times 4] = - 2$$2x + ( - 2) \times 7 = - 2$$x = 8 - 2 = + 6$$2x = 14 - 2 = 12$,$x = \frac{{12}}{2} = + 6$
In this reaction oxidation and reduction are not involved because there is no change in oxidation number.
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$(1)\,\,\begin{array}{*{20}{c}}
{\,\,\,\,\,\,C{H_3}} \\
| \\
{{C_2}{H_5}C{H_2}C - OC{H_3}} \\
| \\
{\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
$(2)\,\,\begin{array}{*{20}{c}}
{{C_2}{H_5}C{H_2}C = C{H_2}} \\
{\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
$(3)\,\,\begin{array}{*{20}{c}}
{{C_2}{H_5}CH = C - C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$