- A$Mn^{+3}$, $Co^{+3}$
- B$Fe^{3+}, Cr^{+3}$
- ✓$Zn^{+2}, Sc^{+3}$
- D$Ti^{+2}, Cu^{+2}$

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,C{H_3}}\\
|\\
{C{H_3} - C - OH}\\
|\\
{\,\,\,\,\,\,\,C{H_3}}
\end{array}}\limits_{\rm{I}} $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,C{H_3}}\\
|\\
{C{H_3} - CH - OH}
\end{array}}\limits_{{\rm{II}}} $ $\mathop {C{H_3} - C{H_2} - OH}\limits_{{\rm{III}}} $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,Ph}\\
|\\
{C{H_3} - C - OH}\\
|\\
{\,\,\,\,\,\,\,{\kern 1pt} C{H_3}}
\end{array}}\limits_{{\rm{IV}}} $

$E$ is


$\begin{array}{*{20}{c}}
{\,\,\,\,\,O} \\
{\,\,\,\,\,||} \\
{HOC{H_2}C{H_2} - C - OC{H_2}C{H_3}}
\end{array}$ $\xrightarrow{{PCC}}(A)\,\xrightarrow[{(1\,\,molar\,\,equivalent)}]{{{H_2}C \equiv CHMgBr}}(B)$ $\xrightarrow{{N{H_4}Cl\,/\,{H_2}O}}\,(C)\,\,\xrightarrow[{{H_2}O}]{{KOH}}\,$ $\xrightarrow{{{H_3}{O^ \oplus }}}\,\,\xrightarrow[{pyridine}]{{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,||} \\
{{{(C{H_3} - C)}_2}O}
\end{array}}}(D)$