Question
Which rational number should be subtracted from $\frac{5}{6}$ to get $\frac{4}{9}$ ?
✓
Answer
Required rational number $=\frac{-5}{6}-\frac{4}{9}$
$\therefore \text{LCM}$ of $6$ and $9=18$
$=\frac{-5 \times 3}{6 \times 3}-\frac{4 \times 2}{9 \times 2} \quad(\therefore\text{ LCM}$ of $6$ and $9=18)$
$=\frac{-15}{18}-\frac{8}{18}$
$=\frac{-15-8}{18}$
$=\frac{-23}{18}$
$=-1 \frac{5}{18}$
| $2$ | $6, 9$ |
| $3$ | $3,9$ |
| $3$ | $1, 3$ |
| $1, 1$ |
$=\frac{-5 \times 3}{6 \times 3}-\frac{4 \times 2}{9 \times 2} \quad(\therefore\text{ LCM}$ of $6$ and $9=18)$
$=\frac{-15}{18}-\frac{8}{18}$
$=\frac{-15-8}{18}$
$=\frac{-23}{18}$
$=-1 \frac{5}{18}$
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