- ✓${H_2} + {I_2}$ $\rightleftharpoons$ $2HI$
- B$2C + {O_2}$ $\rightleftharpoons$ $2CO$
- C${N_2} + 3{H_2}$ $\rightleftharpoons$ $2N{H_3}$
- D$PC{l_5}$ $\rightleftharpoons$ $PC{l_3} + C{l_2}$
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$\left[\mathrm{PtCl}_{4}\right]^{2-}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons\left[\mathrm{Pt}\left(\mathrm{H}_{2} \mathrm{O}\right) \mathrm{Cl}_{3}\right]^{-}+\mathrm{Cl}^{-}$
was measured as a function of concentrations of different species. It was observed that
$\frac{-\mathrm{d}\left[\left[\mathrm{PtCl}_{4}\right]^{2-}\right]}{\mathrm{dt}}=4.8 \times 10^{-5}\left[\left[\mathrm{PtCl}_{4}\right]^{2-}\right]-2.4 \times10^{-3}\left[\left[\mathrm{Pt}\left(\mathrm{H}_{2} \mathrm{O}\right) \mathrm{Cl}_{3}\right]^{-}\right]\left[\mathrm{Cl}^{-}\right]$
where square brackets are used to denote molar concentrations. The equilibrium constant $\mathrm{K}_{\mathrm{c}}=....$. (Nearest integer)
$2X_2 (g) + 2H_2O (l) \to 4H^+ (aq) + 4X^-(aq) + O_2 (g)$
$Y_2 (g) + H_2O (l) \to HY(aq) + HOY(aq)$
$E_{\frac{1}{2}Cl_2/Cl^- }^o = 1.36\,V\,,\,E_{C{r^{3 + }}/Cr}^o = - 0.74\,V$
$E_{C{r_2}O_7^{2 - }/C{r^{3 + }}}^o = 1.33\,V\,,\,E_{MnO_4^ - /M{n^{2 + }}}^o = 1.51\,V$
The correct order of reducing power of the species $(Cr, Cr^{3+}, Mn^{2+}$ and $Cl^-)$ will be
$\mathop {CH_3^ + }\limits_{\rm{I}} $ $\mathop {{H_3}{O^ + }}\limits_{{\rm{II}}} $ $\mathop {N{H_3}}\limits_{{\rm{III}}} $ $\mathop {CH_3^ - }\limits_{{\rm{IV}}} $
| Element | $M^{3+}/ M$ | $M^+/M$ |
| $Al$ | $-1.66$ | $+0.55$ |
| $Tl$ | $+1.26$ | $-0.34$ |
Based on these data, which of the following statements is correct ?