- A${H_2}S{O_4}$
- B$NaCl$
- C$HN{O_3}$
- ✓$N{H_3}$
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$(I)\,\,B{r^ - }{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} $ $(II)\,\,\begin{array}{*{20}{c}}
{{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} O{\mkern 1mu} } \\
{{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} ||} \\
{{H_3}C - C - {O^ - }}
\end{array}$ $(III)\,\,C{H_3}C{H_2}{O^ - }$ $(IV)\,\,Ph - {O^ - }$
${A_2}B(g) \to {A_2}(g) + B(g);\,\,\,\Delta {H^o} = 40\,kJ/mol$
${A_2}B(g) \to A(g) + AB(g);\,\,\,\Delta {H^o} = 50\,kJ/mol$
.....$ kJ/mol$
$(a)$ $H _{2} C _{2} O _{4} \rightleftharpoons H ^{+}+ HC _{2} O _{4}^{-}$
$(b)$ $HC _{2} O _{4}^{-} \rightleftharpoons H ^{+}+ HC _{2} O _{4}^{2-}$
$(c)$ $H _{2} C _{2} O _{4} \rightleftharpoons 2 H ^{+}+ C _{2} O _{4}^{2-}$
The relationship between $K_{a_{1}}, K_{ a _{2}}$ and $K_{ a _{3}}$ is given as