$CS_2 + 3O_2 \to 2SO_2 + CO_2$
Hence for $6$ molecules of Oxygen, we need $2$ molecules $CS _2$
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$n$ $l$ $m$ $s$
$A\, \rightleftharpoons \,B$ ${K_C} = 2$
$B\, \rightleftharpoons \,C$ ${K_C} = 3$
$C\, \rightleftharpoons \,D+E$ ${K_C} = 5$
$K_C$ for the reaction $A\, \rightleftharpoons \,D+E$ is
| Cations | Group reaction |
| $P \rightarrow Pb ^{2+}, Cu ^{2+}$ | $(i)$ $H _2 S$ gas in presence of dilute $HCl$ |
| $Q \rightarrow Al ^{3+}, Fe ^{3+}$ | $(ii)$ $\left( NH _4\right)_2 CO _3$ in presence of $NH _4 OH$ |
| $R \rightarrow Co ^{2+}, Ni ^{2+}$ | $(iii)$ $NH _4 OH$ in presence of $NH _4 CI$ |
| $S \rightarrow Ba ^{2+}, Ca ^{2+}$ | $(iv)$ $H _2 S$ in presence of $NH _4 OH$ |
[Given : $R_{\mathrm{H}}\left(\right.$ Rydberg constant) $=2.18 \times 10^{-18} \mathrm{~J}$.
$h($ Plank's constant $)=6.6 \times 10^{-34}$ J.s. $]$