MCQ
Which statement is incorrect
- AIonisation potential order : $F^-< Cl^-$
- BElectron Affinity order : $F < Cl$
- CIonisation potential order : $O^-< S^-$
- ✓Electronegativity order : $sp^3 > sp$ (for hybrid carbon atom)
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$(A)$ Compounds $P$ and $Q$ are carboxylic acids.
$(B)$ Compound $S$ decolorizes bromine water.
$(C)$ Compounds $P$ and $S$ react with hydroxylamine to give the corresponding oximes.
$(D)$ Compound $R$ reacts with dialkylcadmium to give the corresponding tertiary alcohol.
trans $\left( Ph - CH = CH - CH _3\right) \rightarrow$ cis $\left( Ph - CH = CH - CH _3\right)$
| Compound | $K_{sp}$ |
| $AgCl$ | $1.1\times10^{-10}$ |
| $AgI$ | $1.0\times10^{-16}$ |
| $PbCrO_4$ | $4.0\times10^{-14}$ |
| $Ag_2CO_3$ | $8.0\times10^{-12}$ |
The most soluble and least soluble compounds are respectively.