MCQ
Which statement is not correct for nitrogen
- AIt has a small size
- BIt does not readily react with ${O_2}$
- CIt is a typical non-metal
- ✓$d$ - orbitals are available for bonding
$d$ - orbitals are absent in nitrogen.
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Compound $(C)$ can show geometrical isomerism. Product $(E)$ of the reaction will be
| List $I$ Oxide | List $II$ Type of Bond |
| $A$ $N _2 O _4$ | $I$. $1 N = O$ bond |
| $B$ $NO _2$ | $II$. $1 N - O - N$ bond |
| $C$ $N _2 O _5$ | $III$. $1 N - N$ bond |
| $D$ $N _2 O$ | $IV$. $1 N = N / N \equiv N$ bond |
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