Which term of G.P. 25, 125, 625, …………. is 390625? - Vidyadip

MCQ

Which term of G.P. 25, 125, 625, …………. is 390625?

A
5
B
6
C
7
D
8

✓

Answer

7

Solution:

In the given G.P., In the given G.P., a=25 and

$\text{r}=\frac{125}{25}=5$

Given, a_n = 390625 ⇒ ar^n-1 = 390625

⇒ 25 × 5^n-1 = 390625

$\Rightarrow5^\text{n-1}=\frac{390625}{25}=15625=5^6$

=> n-1 = 6 => n=7.

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