Question
Which term of the A.P. 53, 48, 43,… is the first negative term?

Answer

Let $n$th term is the first negative term of the A.P. $53,48,43, \ldots$
Here, $a=53, d=48-53=-5$
$
\begin{aligned}
& \therefore T_n=a+(n-1) d \\
& =53+(n-1) \times(-5) \\
& =53-5 n+5 \\
& =58-5 n
\end{aligned}
$
$
\begin{aligned}
& 5 n=58 \\
& n=\frac{58}{5} \\
& =11 \frac{3}{5}
\end{aligned}
$
$\therefore 12$ th term will be negative.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free