MCQ
While doing his experiment, Millikan one day observed the following charges on a single drop
$(i)\ 6.563 \times 10^{-19} \mathrm{C}$
$(ii)\ 8.204 \times 10^{-19} \mathrm{C}$
$(iii)\ 11.50 \times 10^{-19} \mathrm{C}$
$(iv)\ 13.13 \times 10^{-19} \mathrm{C}$
$(v)\ 16.48 \times 10^{-19} \mathrm{C}$
$(vi)\ 18.09\times 10^{-19} \mathrm{C}$
From this data the value of the elementary charge $(e)$ was found to be
$(i)\ 6.563 \times 10^{-19} \mathrm{C}$
$(ii)\ 8.204 \times 10^{-19} \mathrm{C}$
$(iii)\ 11.50 \times 10^{-19} \mathrm{C}$
$(iv)\ 13.13 \times 10^{-19} \mathrm{C}$
$(v)\ 16.48 \times 10^{-19} \mathrm{C}$
$(vi)\ 18.09\times 10^{-19} \mathrm{C}$
From this data the value of the elementary charge $(e)$ was found to be
- ✓$1.641 \times 10^{-19} \mathrm{C}$
- B$1.630 \times 10^{-19} \mathrm{C}$
- C$1.648 \times 10^{-19} \mathrm{C}$
- D$1.602 \times 10^{-19} \mathrm{C}$