Question
Why do noble gases have comparatively large atomic sizes?
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Answer
The atomic radii of noble gases are by far the largest in their respective periods. This is due to the reason that noble gases (because they do not form molecules) have only vander Waals radii while others have covalent radii. As we move down the group at the atomic radii further increase is primarily due to increase in the number of shells.
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Match the starting materials given in Column $I$ with the products formed by these $($Column $II)$ in the reaction with $II.$
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Column $I$
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Column $II$
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| $(i)$ | $CH_3-o-CH_3$ | $(a)$ |
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| $(ii)$ |
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$(b)$ |
$\ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3 \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \\ \text{CH}_3-\text{C}-\text{I}+\text{CH}_3\text{OH} \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$
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| $(iii)$ |
$\ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3 \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \\ \text{H}_3\text{C}-\text{C}-\text{O}-\text{CH}_3 \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$
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$(c)$ |
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| $(iv)$ |
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$(d)$ | $CH_3-OH + CH_3-I$ |
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$(e)$ |
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$(f)$ |
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$(g)$ |
$\ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3 \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \\ \text{CH}_3-\text{C}-\text{OH}+\text{CH}_3\text{I} \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$
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