Question
Why does a light ray incident on a rectangular glass slab immersed in any medium emerges parallel to itself? Explain using a diagram.

Answer

Perform an experiment to demonstrate that light bends from its path, when it falls obliquely on the surface of a glass slab. Also show that angle of incidence is about equal to the emergent angle.
  1. Take a glass slab and place it on a white sheet of paper fixed on a drawing board.
  2. Mark the boundary ABCD of the glass slab.
  3. Fix two pins $P_1$ and $P_2$, vertically on the drawing board such that line joining the pins is inclined to the edge $A B$ of the glass slab (Figure).

4. Now, look through the glass slab from opposite side so that the images of pins $P _1$ and $P _2$ are seen exactly in line. Fix two pins $P_3$ and $P_4$, vertically on the drawing board such that pins $P_3, P_4$ and image of $P_1$ and $P_2$ are exactly in one line.
5. Remove the glass slab and all pins. Join the points $P_1$ and $P_2$ with a line and extend this line to touch the edge $A B$ at $P$. Similarly join the points $P_3$ and $P_4$ with a line and extend the line to touch the edge $D C$ at $Q$.
6. Join points $P$ and $Q$ with a straight line.
7. Draw normal $N N^{\prime}$ at $P$ on the edge $A B$ and a normal $N_1 N_1{ }^{\prime}$ at $Q$ on the edge $D C$.
8. Measure $\angle P _2 PN$ and $\angle P _3 QN _1^{\prime}$ using a protractor or dee.

This experiment shows that when light falls obliquely on a glass slab, it bends along PQ from its original path along PL . Also $\angle P _2 PN \approx \angle P _3 QN _1^{\prime}$. That is, angle of incidence is about equal to the emergent angle.Note: Distance between pins $P_1$ and $P_2$, and between $P_3$ and $P_4$ must be large.

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