Question
Why geometry of $BF _3$ is triangular while that of $NH _3$ is pyramidal? Give reason.
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Answer
In $BF _3, B$ have $s p^2$ hybridisation ( $3 \sigma$ bond). Hence its geometry is triangular. While in $NH _3, N$ have $3 \sigma$ bond and as it have one 1.p electron it have $s p^3$ hybridisation. Hence its geometry is pyramidal.
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