MCQ
With increasing principal quantum number, the energy difference between adjacent energy levels in $H-$ atom
- ✓decreases
- Bincreases
- Cremains constant
- Ddecreases for high value of $z$ and increases for low value of $z$
✓
Answer
Correct option: A.
decreases
a
$\mathrm{E}_{2}-\mathrm{E}_{1}=13.6 \times 1^{2}\left(\frac{1}{1^{2}}-\frac{1}{2^{2}}\right)=13.6 \times \frac{3}{4}$
$\mathrm{E}_{2}-\mathrm{E}_{1}=13.6 \times 1^{2}\left(\frac{1}{1^{2}}-\frac{1}{2^{2}}\right)=13.6 \times \frac{3}{4}$
$\mathrm{E}_{3}-\mathrm{E}_{2}=13.6 \times 1^{2}\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)=13.6 \times \frac{5}{36}$
$\mathrm{E}_{4}-\mathrm{E}_{3}=13.6 \times 1^{2}\left(\frac{1}{3^{2}}-\frac{1}{4^{2}}\right)=13.6 \times \frac{9}{144}$
Energy difference decreases as principal quantum number increases
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