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$\begin{array}{l}x^2+2 \sqrt{3} x+3=0 \text { compare with } a x^2+b x+c=0 \\ \Rightarrow a=1, b=2 \sqrt{3} \text { and } c=3 \\ \therefore b^2-4 a c=(2 \sqrt{3})^2-4(1)(3) \\ =12-12 \\ =0 \\ x=\frac{-b \pm \sqrt{b^2-4 a c}}{2 a} \\ \Rightarrow x=\frac{-2 \sqrt{3} \pm \sqrt{0}}{2 \times 1}\end{array}$
$\Rightarrow x=\frac{-2 \sqrt{3}}{2}$
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