Question
Without actual division, show that the following rational numbers is a non-terminating repeating decimal:$\frac{73}{\big(2^2\times3^3\times5\big)}$
✓
Answer
$\frac{73}{\big(2^2\times3^3\times5\big)}$We know 2, 3 or 5 is not a factor of 73, so it is in its simplest form.
Moreover,$ (2^2 \times 3^3 \times 5) \neq (2^m \times 5^n)$
Hence, the given rational is non-terminating repeating decimal.
Moreover,$ (2^2 \times 3^3 \times 5) \neq (2^m \times 5^n)$
Hence, the given rational is non-terminating repeating decimal.
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