Question
Without actual division, show that the following rational numbers is a terminating decimal. Express in decimal form:$\frac{23}{\big(2^3\times5^2\big)}$
✓
Answer
$\frac{23}{2^3\times5^2}=\frac{23\times5}{2^3\times5^3}$$=\frac{115}{1000}=0.115$
We know either 2 or 5 is not a factor of 23, so it is in its simplest form.
Moreover, it is in the form of $(2^m\times 5^n).$
Hence, the given rational is terminating.
We know either 2 or 5 is not a factor of 23, so it is in its simplest form.
Moreover, it is in the form of $(2^m\times 5^n).$
Hence, the given rational is terminating.
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