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Real Numbers — Maths STD 10 — Question

Maharashtra BoardEnglish MediumSTD 10MathsReal Numbers1 Mark
Question
Without actual division, show that the following rational numbers is a terminating decimal. Express in decimal form:$\frac{23}{\big(2^3\times5^2\big)}$
✓

Answer

$\frac{23}{2^3\times5^2}=\frac{23\times5}{2^3\times5^3}$$=\frac{115}{1000}=0.115$
We know either $2$ or $5$ is not a factor of $23$, so it is in its simplest form.
Moreover, it is in the form of $(2^m\times 5^n)$.
Hence, the given rational is terminating.

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