Question
Without solving the following quadratic equation, find the value of 'm' for which the given equation has real and equal roots.
$x^2+ 2 (m - 1) x + (m + 5) = 0.$
$x^2+ 2 (m - 1) x + (m + 5) = 0.$
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| $x$ | $5$ | $10$ | $15$ | $20$ | $25$ | $30$ | $35 $ | $40$ | $45$ | $50$ |
| $f$ | $20$ | $43$ | $75$ | $67$ | $72$ | $45$ | $39$ | $9$ | $8$ | $6$ |