Question
Without using truth table prove that:
~ (p ∨ q) ∨ (~ p ∧ q) ≡ ~ p
~ (p ∨ q) ∨ (~ p ∧ q) ≡ ~ p
R.H.S. = ∼p
L.H.S. = R.H.S.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| $X=x$ | $0$ | $1$ | $2$ | $3$ | $4$ |
| $P(X=x)$ | $0.1$ | $K$ | $2K$ | $2K$ | $K$ |
~ p ∧ (q ∨ ~ r)
$\int_0^1 \log \left(\frac{1}{x}-1\right) \cdot d x$