MCQ
Work done for the process shown in the figure is ............ $J$


- A$1$
- B$1.5$
- C$4.5$
- ✓$0.3$

Area under graph and $V$ axis $=$ work done
$=\frac{1}{2} \times(30+10) \times 10^3 \times(25-10) \times 10^{-6}$
$=0.3 \,J$
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(given atmospheric pressure $P_{A}=1.01 \times 10^{5}\,Pa$, density of water $\rho_{ w }=1000\,kg / m ^{3}$ and gravitational acceleration $g=10\,m / s ^{2}$ )