Gujarat BoardEnglish MediumSTD 8MATHSSquares and Square Roots1 Mark
Question
Write a Pythagorean triplet whose one member is 14
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Answer
Given number is 14. On putting 2m = 14 $\Rightarrow \quad m=7$ So, $m^2-1=7^2-1=49-1=48$ and $m^2+1=7^2+1=49+1=50$ Hence, (14, 48, 50) is a Pythagorean triplet.
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