Question
Write a Pythagorean triplet whose one member is
14

Answer

Given number is 14.
On putting 2m = 14
$\Rightarrow \quad m=7$
So, $m^2-1=7^2-1=49-1=48$
and $m^2+1=7^2+1=49+1=50$
Hence, (14, 48, 50) is a Pythagorean triplet.

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