Question
Write a Pythagorean triplet whose one member is
6

Answer

Given number is 6.
On putting 2m = 6
$\Rightarrow \quad m=\frac{6}{2}=3$
$\text { So, } m^2-1=3^2-1=9-1=8$
$\text { and } m^2+1=3^2+1=9+1=10$
Hence, (6, 8, 10) is a Pythagorean triplet.

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