Question
Write an expression for Ka, for ionisation of HCN in aqueous solution. Give equation also.

Answer

$\text{HCN}+\text{H}_2\text{O}\rightleftharpoons\text{H}_3\text{O}^{\oplus}+\text{CN}^-$

$\text{K}_{\text{a}}=\frac{[\text{H}_3\text{O}^+][\text{CN}^-]}{[\text{HCN}]}$

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