MCQ
Write hybridisation of carbon atoms as indicated :
- ✓$ a=s p^2, b=s p^3, c=s p^3, d=s p^2 $
- B$ b=s p^2, a=s p^3, c=s p^3, d=s p^2$
- C$ c=s p^2, b=s p^3, a=s p^3, d=s p^2$
- DNone of these
✓
Answer
Correct option: A.
$ a=s p^2, b=s p^3, c=s p^3, d=s p^2 $
Carbon $(a)$ forms $2$ sigma bond and $1$ pi bond, So it is $\mathrm{sp}^2$
Carbon $(b)$ forms $4$ sigma bond, so it is $\mathrm{sp}^3$
Carbon $(c)$ forms $4$ sigma bond, so it is $\mathrm{sp}^3$
Carbon $(d)$ forms $1$ pi bond and $2$ sigma bond, So it is $\mathrm{sp}^2$
Carbon $(b)$ forms $4$ sigma bond, so it is $\mathrm{sp}^3$
Carbon $(c)$ forms $4$ sigma bond, so it is $\mathrm{sp}^3$
Carbon $(d)$ forms $1$ pi bond and $2$ sigma bond, So it is $\mathrm{sp}^2$
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