Question
Write the cell representation and calculate equilibrium constant for the following redox reaction:
$Ni _{( s )}+2 Ag ^{+}( aq )(1 M ) \rightarrow Ni ^{2+}( aq )(1 M )+2 Ag _{( s )}$
$ \text { at } 25^{\circ} C$
$ E _{ Ni }^0=-0.25 V \text { and } E _{ Ag }^0=0.799 V$

Answer

Given : $E ^0_{ Ni ^2+/Ni } =-0.25 V; E _{ Ag ^{+} / Ag }^0=0.799 V$
Equilibrium constant $= K = ?$
$Ni _{( s )}\left| Ni _{( aq )}^{2+}(1 M )\right|\left| Ag _{\text {(aq) }}^{+}(1 M )\right| Ag _{( s )}$
$ E_{ cell }^0=E_{ Ag ^{+} / Ag }^0-E_{ Ni ^2+/ Ni }^0$
$ =0.799-(-0.25)$
$ =1.049 V $
$ =0.799-(-0.25)$
$=1.049 V$
$E_{\text {cell }}^0=\frac{0.0592}{n} \log _{10} K$
$\therefore \log _{10} K=\frac{n \times E_{\text {cell }}^0}{0.0592}$
$=\frac{2 \times 1.049}{0.0592}$
$=35.44$
$\therefore K=\text { antilog } 35.44$
$=2.754 \times 10^{35} $
Equilibrium constant $=K=2.754 \times 10^{35}$

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